WWTBAM Bored

Last night, for the first time since baseball expanded to 12 teams per league in 1969, all the home teams won on a day with a full slate of games. Four of the 15 wins were walkoffs. In 1914, when there were considered to be three major leagues (counting the Federal League), all 12 teams won one day, and once in 1989, all the home teams won on a day in which there were 11 games on the schedule. According to STATS, viewing each game as a 50/50 proposition, the odds on that happening are one in 32,768/

http://espn.go.com/mlb/story/_/id/13421 ... going-15-0

Thanks to the Red Sox bullpen...

The way I heard it said, it was the first time "in history" that all 15 home teams won on the same day. But that has only been possible since MLB expanded to 30 teams in 1998.

elwoodblues wrote:The way I heard it said, it was the first time "in history" that all 15 home teams won on the same day. But that has only been possible since MLB expanded to 30 teams in 1998.

Would it have counted when there were, say, only 26 teams, and four teams were playing double-headers? (Of course, the double-header is rather rare these days.)

elwoodblues wrote:The way I heard it said, it was the first time "in history" that all 15 home teams won on the same day. But that has only been possible since MLB expanded to 30 teams in 1998.

According to the article, the previous record was 12 in1914, which of course comes with a big asterisk, since it includes the Federal League. I would think that doubleheaders would count since it's "most wins without a loss for home teams." Since the old record (based on just the AL and NL) was 11, it means there was never a full slate of games since expansion in 1969 with all wins for the home team.